Limits are tricky in higher dimensions because there are many ways to approach a point.
If f is a continuous function, limx→af(x)=f(a)
Most functions are built up from continuous functions of one variable using artihemtic operations and composition, which all preserve unity except for division.
Theorem 1.9. Suppose f:Rn→Rm is continuous on U⊂Rn and g:Rm→Rk is continuous on f(U)⊂Rm. Then the composite function g∘f:U→Rk is continuous on U.
Theorem 1.10. Let f1(x,y)=x+y,f2(x,y)=xy, and g(x)=1/x. Then f1 and f2 are continuous on R2 and g is continuous on R∖{0}.
Corollary 1.11. The function f3(x,y)=x−y is continuous on R2, and the function f4(x,y)=x/y is continuous on {(x,y):y=0}.
Corollary 1.12. The sum, product, or difference of two continuosu functions is continuous; the quotient of two continuous functions is continuous on the set where the denominator is nonzero.
Theorem 1.13. Suppose f:Rn→Rk is continuous and u⊂Rk. Let S={x∈Rn:f(x)∈U}. Then S is open if U is open and S is closed if U is closed.
1.5: Completeness
The essential properties of the real number system which underlies all of calculus: R is a complete ordered field.
Field: operations of addition, subtraction, multiplication, and division are defined and subjec to usual laws of arithmetic.
Ordered field: field with the binary relation and antisymmetric
Completeness: there are no ‘holes’ in the real number line
If S is a subset of R, an upper bound for S is a number u such that x≤u for all x∈S, and a lower bound for S is a number l such that l≤x for all x∈S.
The Completeness Axiom. Let S be a nonempty set of real numbers. If S has an upper bound, then S has a least upper bound, the supremum of S, denoted supS. If S has a lower bound, then S has a greatest lower bound, the infimum of S, denoted infS. Examples:
S=(0,1]. supS=1, infS=0.
S={1,1/2,1/3,1/4,...}. supS=1, infS=0.
S={1,2,3,4,...}. supS=∞, infS=1.
If S has an upper bound, the number a=supS is the unique number such that
x≤a for all x∈S (a is an upper bound)
For every ϵ>0, there exists x∈S with x>a−ϵ (there is no smaller upper bound)
Completeness of the real number system is important in establishing the convergence of numerical sequences
A sequence is bounded if its range is bounded
A sequence is increasing if xn+1≥xn for all n
A sequence is decreasing if xn+1≤xn for all n
A sequence is monotonic if it is either increasing or decreasing
Theorem 1.16 (Monotone Sequence Theorem). Every bounded monotone sequence in R is convergent. The limit of an increasing/decreasing sequence is the supremum/infimum of its set of values.
Theorem 1.17 (Nested Interval Theorem). Let I1=[a1,b1],I2=[a2,b2],... be a squence of closed, bounded intervals in R. Suppose that I1⊃I2⊃I3⊃...and the length bk−ak of Ik approaches 0 as k→∞. Then there is eactly one point contained in all of the intervals Ik. The intersection ⋂k=1∞Ik is nonempty (a single point).
A subsequence of {xk} is a sequence specified by a one-to-one map j→kj from the set of positive integers into itself, e.g. $k_j = 2j$$ selected even-numbered terms.
Theorem 1.18 (form of Bolzano-Weierstrass theorem). Every bounded sequence in Rn has a convergent subsequence.
A sequence {xk}∈Rn is a Cauchy sequence if xk−xj→0 as k,j→∞; that is, if for every ϵ>0 there exists an integer K such that ∣xk−xj∣<ϵ whenever k>K and j>K.
Theorem 1.20. A sequence {xk}∈Rn is convergent iff it is Cauchy.
1.6: Compactness
A subset of Rn is compact if it is closed and bounded.
Compactness is important because it yields existence theorems for limits.
Theorem 1.21 (Bolzano-Weierstrass Theorem). If S is a subset of Rn, S is compact iff every sequence of points in S has a convergent subsequence whose limit lies in S.
Note: every finite subset of Rn is obviously compact
Connection between compactness and continuity
Theorem 1.22. Continuous functions map compact sets to compact sets. Suppose that S is a compact subset of Rn and f:S→Rm is continuous at every point of S. Then the set f(S)={f(x):x∈S} is also compact.
Theorem 1.23 (Extreme Value Theorem). Suppose S⊂Rn is compact and f:S→R is continuous. Then f has an absolute minimum value and an absolute maximum value on S; that is, there exist points a,b∈S such that f(a)≤f(x)≤f(b) for all x∈S.
U is a collection of subsets Rn. It is a covering of S if S is contained within the union of the sets in U.
Theorem 1.24 (Heine-Borel Theorem). If S is a subset of Rn, then S is compact iff every open covering of S has a finite subcovering.
Metric spaces: general spaces equipped with a distance function.
But Bolzano-Weierstrass and Heine-Borel may not be completely valid for other metric spaces.
1.7: Connectedness
A set in Rn is connected if it is ``all in one piece’’
A set is disconnected if it is the union of two nonempty sets, neither of which intersects the closure of the other.
A set is connected if it is not disconnected.
Theorem 1.25. The connected subsets of R are precisely the intervals (open, half-open, or closed; bounded or unbounded).
Theorem 1.26. Cotninuous functions map connected sets to connected sets.
Corollary 1.27. (The Intermediate Value Theorem.) Suppose f:S→R is continuous at every point of S and V⊂S is connected. If a,b∈V and f(a)<t<f(b) or f(b)<t<fa), there is a point c∈V such that f(c)=t.
A set is arcwise/pathwise connected if any two points in S can be joined by a continuous curve in S.
Theorem 1.28. If S⊂Rn is arcwise connected, then S is connected.
Theorem 1.30. If S⊂Rn is open and connected, then S is arcwise connected.
Chapter 2: Differential Calculus
2.1: Differentiability in One Variable
A more useful notion of the derivative than in elemetnary calculus books
f:R→R is differentiable at x=a if it is approximately linear near x=a.
That is, there exists a linear function l(x)=mx+b satisfying l(a)=f(a), i.e. l(x)=f(a)+m(x−a).
The linear approximation f(x)−l(x) must go to zero faster than x−a as x→a (i.e. faster than x approaches a), so we have
x−af(x)−l(x)→0,x→a
Let h=x−a. Then
f(x)−l(x)=f(a+h)−f(a)−mh
We have the error function E(h)=f(x)−l(x)=f(a+h)−f(a)−mh, which is the difference between the function and its linear approximation.
Formal definition. f is a real-valued function on an open interval in R containing a. f is differentiable at a if there exists some number m such that
E(h) is little-oh of h, i.e. it is of a smaller order of magnitude than h.
f(a+h) is the sum of a linear function of h and an error term which is o(h).
We can work out standard differentiation rules from this definition.
The Product Rule. Suppose f and g are differentiable at x=a. Then f(a+h)=f(a)+f′(a)h+E1(h) and g(a+h)=g(a)+g′(a)h+E2(h), where E1(h) and E2(h) are both o(h). Then we get
Left-hand derivative f−′(a) and right-hand derivative f+′(a):
f±′(a)=h→0±limhf(a+h)−f(a)
Mean Value Theorem. Definition of derivative: passing from local information given by values of f(x) for x near a to the infinitesimal information f′(a). How to go from infinitesimal information to local information? i.e. explain information about f given f′?
Proposition 2.5. Suppose f is defined on an open interval I and a∈I. If f has a local maximum or minimum at the point a∈I and f is differentiable at a, then f′(a)=0.
Lemma 2.6 – Rolle’s Theorem. Suppose f is continuous on [a,b] and differentiable on (a,b). If f(a)=f(b), then there is at least one point c∈(a,b) such that f′(c)=0.
Theorem 2.7 – Mean Value Theorem I. Suppose f is continuous on [a,b] and differentiable on (a,b). There is at least one point c∈(a,b) such that f′(c)=b−af(b)−f(a)
Theorem 2.8. Suppose f is differentiable on the open interval I.
If ∣f′(x)∣≤C for all x∈I, then ∣f(b)−f(a)∣≤C∣b−a∣ for all a,b∈I.
If f′(x)=0 for all x∈I, then f is constant on I.
If f′(x)≥0 for all x∈I, then f is increasing on I.
Theorem 2.9 – Mean Value Theorem II. Suppose f,g are continuous on [a,b] and differentiable on (a,b); and g′(x)=0 for all x∈(a,b). Then there is a point c∈(a,b) such that g′(c)f′(c)=g(b)−g(a)f(b)−f(a)
Theorem 2.10 – L’Hopital’s Rule I. Suppose f,g are differentiable functions on (a,b) and limx→a+f(x)=limx→a+g(x)=0. If g′ never vanishes on (a,b) and the limit limx→a+g′(x)f′(x)=L exists, then g never vanishes on (a,b) and limx→a+g(x)f(x)=L. The same result holds for the left-handed limit, the two-sided limit, and limits to infinity or negative infinity.
Theorem 2.11 – L’Hopital’s Rule II. Thoerem 2.10 remains value when the limits of f(x) and g(x) go to infinity.
The mean value theorem is not valid for vector-valued functions.
2.2: Differentiability in Several Variables
2.7: Taylor’s Theorem
Taylor expansions in their finite form
Taylor’s theorem – higher-order version of the tangent line approximation.
A function f of class Ck on an interval I containing the point x=a is the sum of a certain polynomial of degree k and a remainder term that vanishes more rapidly than ∣x−a∣k as x→a
The polynomial P=Pa,k of order k such that P(j)(0)=f(j)(a) for 0≤j≤k; the kth-order Taylor polynomial for f based at a:
The Taylor polynomial is a good approximation of f near a.
Theorem 2.55. – Taylor’s Theorem with Integral Remainder, I. Suppose that f is of class Ck+1, with k≥0 on an interval I⊂R, and a∈I. Then the remainder Ra,k defined by 2.53 - 2.54 is given by
Ra,k(h)=k!hk+1∫01(1−t)kf(k+1)(a+th)dt.
Theorem 2.58. – Taylor’s Theorem with Integral Remainder, II. Suppose that f is of class Ck, k≥1 on an interval I⊂R, and a∈I. Then the remainder Ra,k is given by
Corollary 2.60. If f is of class Ck on I, then Ra,k(h)/hk→0 as h→0.
If f is Ck near x=a, we can write f(x) as the sum of a k-th order polynomial
Corollary 2.61. If f is of class Ck+1 on I and ∣f(k+1)(x)∣≤M for x∈I, then
∣Ra,k(h)∣≤(k+1)!M∣h∣k+1,a+h∈I
Lemma 2.62. suppose g is k+1 times differentiable on [a,b]. If g(a)=g(b) and g(j)(a)=0for441≤j≤k, then there is a point c∈(a,b) such that g(k+1)(c)=0
Theorem 2.63. – Taylor’s Theorem with Lagrange’s Remainder. Suppose f is k+1 times differentiable on an interval I∈R, and a∈I. For each h∈R such that a+h∈I, there is a point c between 0 and h such that
Proposition 2.65. The Taylor Polynomials of degree k about a=0 are:
For ex: ∑0≤j≤kj!xj
For cosx: ∑0≤j≤k/2(2j)!(−1)jx2j
For sinx: ∑0≤j≤(k−1)/2(2j+1)!(−1)jx2j+1
For (1−x)−1: ∑0≤j≤kxj
Taylro polynomials can approximate complicated functions with easier computations
Theoretically, importantly, the behavior of any function near some point is determined by the first nonvanishing term
Suppsoe f:Rn→R is of class Ck on a convex open set S. We can derive a Taylor expansion for f(x) about a point a∈S by looking at the restriction of f and the line joining a and x.
With h=x−a and g(t)=f(a+t(xa))=f(a+th); so g′(t)=h⋅∇f(a+th)
Theorem 2.68. – Taylor’s Theorem in Several Variables. Suppose f:Rn→R is a class Ck on an open convex set S. If a∈S and a+h∈S. Then
f(a+h)=∣α∣≤k∑α!∂αf(a)hα+Ra,k(h)
Corollary 2.75. If f is of class Ck on S, then Ra,k(h)/∣h∣k→0 as h→0.
Lemma 2.76. If P(h) is a polynomial of degree ≤k that vanishes to order >k as h→0.
Theorem 2.77. Suppose f is of class C(k) near a. If f(a+h)=Q(h)+E(h) where Q is a polynomial of degree ≤k and E(h)/∣h∣k→0 as h→0, then Q is the Taylor polynomial Pa,k.
2.8: Critical Points
a∈S is a critical point for f if ∇f(a)=0.
f has a local maximum at a if f(x)≤f(a) for all x in some neighborhood of a
Proposition 2.78. If f has a local max or min at a and f is differentiable at a, then ∇f(a)=0.
How can we tell if a function has a local maximum or minimum?
If f is of class C2, then f has a local min at a if f′′(a)>0.
Definition. Suppose f is a real-valued function of class C2 on some open set S⊂Rn and f has a critical point at a. One needs an n×n matrix H
Spectral theorem: every symmetric matrix has an orthonormal eigenbasis
Theorem 2.81. Suppose f is of class C2 at a and that ∇f(a)=0, and let H be the Hessian matrix. For f to have a local min at a, it is necessary for the eigenvalues of H all to be nonnegative and sufficient for them all to be strictly positive. For f to hav ea local max at a, it is necessary for the eigenvalues of H all to be nonpositive and sufficient for them all to be strictly negative.
If two eigenvalues have opposite signs, f has a saddle point.
A critical point for which zero is an eigenvalue of the Hessian is degenerate (like Vivek)
Theorem 2.8. Suppose f is of class C2 on an open set in R2 containing the point a, and suppose ∇f(a)=0. Let α=∂12f(a),β=∂1∂2f(a),γ=∂22f(a).
If αγ−β2<0, f has a saddle point at a.
If αγ−β2>0 and α>0, f has a local min at a.
If αγ−β2>0 and α<0, f has a local max at a.
If αγ−β2=0, the test is inconclusive.
2.10: Vector-Valued Functions and Their Derivatives
It can be useful to consider vector-valued functions – i.e. mappings from Rn to Rm, n,m>0∈Z.
f(x)=(f1(x),f2(x),...,fm(x))
A mapping f from S∈Rn to Rm is differentiable at a∈S if ∃ an m×n matrix L such that
h→0lim∣h∣∣f(a+h)−f(a)−Lh=0
There can only be one such derivative, the Frechet derivative. – Df(a).
Proposition 2.85. An Rm-valued function f is differentiable at a precisely when each of its components f1,...,fm is differentiable at a. Df(a) is a matrix whose jth row is the row vecvtor ∇fj(a).
Theorem 2.86. – Chain Rule III. Suppose g:Rk→Rn is differentiable at a∈Rk and f:Rn→Rm is differentiable at g(a)∈Rn. H=f∘g:Rk→Rm is differentiable at a, and
DH(a)=Df(g(a))Dg(a)
where the expression on the right is the product of the matrices Df(g(a)) and Dg(a).
Definition. Norm of a linear mapping is the smallest constant C such that $$\vert A\mathbf{x} \vert \le C \vert x \vert4$
Theorem 2.88. Suppose f is a differentiable Rm-valued function on an open convex set S⊂Rn, and suppose that ∥Df(x)∥≤M for all x∈S. Then
Lemma 4.3. If P′ is a refinement of P, then sP′f≥sPf and Sp′f≤SPf.
Lemma 4.4. If P and Q are any partitions of [a,b], then sPf≤SQf
Lower integral of f on [a,b]: Lab(f)=supPsPf
Upper integral of f on [a,b]: Iab(f)=infPSpf
(Supremum and infimum are taken over all partitions of [a,b])
Riemann vs. Lebesgue integral.
Lemma 4.5. (important!): If f is a bounded function on [a,b], the following conditions are equivalent:
f is integrable on [a,b]
For every ϵ>0 there is a partition P of [a,b] such that SPf−sPf<ϵ
For any partition P, we have
sPf≤∫abf(x)dx≤SPf
If SPf−sPf<ϵ, SPf and sPf are both within ϵ of ∫abf(x)dx.
Theorem 4.6.
Suppose a<b<c. If f is integrable on [a,b] and on [b,c], then f is integrable on [a,c], and ∫acf(x)dx=∫abf(x)dx+∫bcf(x)dx
If f,g are integrable on [a,b], then so is f+g, and ∫ab[f(x)+g(x)]dx=∫abf(x)dx+∫abg(x)dx.
Observe negation and ordering of bounds:
∫baf(x)dx=−∫abf(x)dx
Theorem 4.9. Properties of functions integrable on [a,b]
If c∈R, then cf is integrable on [a,b], and fabcf(x)dx=c∫abf(x)dx
If [c,d]∈[a,b], then f is integrable on [c,d]
If g is integrable on [a,b] and f(x)≤g(x) for x∈[a,b], then fabf(x)dx≤fabg(x)dx
Theorem 4.10. If f is bounded and monotone on [a,b], then f is integrable on [a,b]. Proof sketch:
Suppose f is increasing on [a,b].
Consider the partition Pk of [a,b] into k equal subintervals
The difference between the lower and upper Riemann sums is k(b−a)[f(b)−f(a)]
We can make k sufficiently large, so f is integrable
Theorem 4.11. If f is continuous on [a,b], then f is integrable on [a,b].
We know that f is uniformly continuous on [a,b]
Theorem 4.12. If f is bounded on [a,b] and continuous at all except finitely many points in [a,b], then f is integrable on [a,b]
A set Z∈R has zero content if for any ϵ>0, there is a finite collection of intervals I1,...,IL such that Z∈⋃1LIl and the sum of lengths of the Il’s is less than ϵ.
Theorem 4.13. If f is bounded on [a,b] and the set of points in [a,b] at which f is discontinuous has zero content, then f is integrable on [a,b]
Proposition 4.14. Suppose f and g are integrable on [a,b] and f(x)=g(x) for all except finitely many points x∈[a,b]. Then fabf(x)dx=fabg(x)dx
Theorem 4.15. (The Fundamental Theorem of Calculus)
Let f be an integrable function on [a,b]. For x∈[a,b], let F(x)=∫axf(t)dt. Then F is continuous on [a,b]; moreover, F′(x) exists and equals f(x) at every x at which f is continuous.
Let F be a continuous function on [a,b] that is differentiable except perhaps at finitely many points in [a,b], and let f be a function on [a,b] that agrees with F′ at all points where the latter is defined. If f is integrable on [a,b], then fabf(t)dt=F(b)−F(a)
Given an integrable function f on [a,b], for which partitions P do the sums sPf and SPf give a good approximation of ∫abf(x)dx?
Proposition 4.16. Suppose f is integrable on [a,b]. Given ϵ>0, there exists δ>0 such that if P={x0,...,xJ} is any partition of [a,b] satisfying max1≤j≤J(xj−xj−1)<δ, the sums sPf and SPf differ from ∫abf(x)dx by at most ϵ.
The definite integral – good to understand as a sum of infinitely many infinitesimal terms.
4.2: Integration in Higher Dimensions
Rectangle: a set of the form R=[a,b]×[c,d]
Partition of R: a subdivision of R into rectangles by partitioning both sides of R
f is Riemann integrable on R if the lower and upper integrals coincide: ∫∫RfdA=∫∫Rf(x,y)dxdy
How can we integrate over regions other than rectangles?
Draw a large rectangle containing S, redefine f to be zero outside of S, and integrate over R.
Characteristic / indicator function of S: χS(x)=1 if x∈S,0 otherwise
f is integrable on S if fχS is integrable on R
∫∫SfdA=∫∫RfχSdA
Theorem 4.17.
If f1,f2 are integrable on the bounded set S and c1,c2∈R, then c1f1+c2f2 is integrable on S, and ∫∫S[c1f1+c2f2]dA=c1∫∫Sf1dA+c2∫∫Sf2dA
Let S1,S2 be bounded sets with no points in common, and let f be a bounded function. If f is integrable on S1 and on S2, then f is integrable on S1∪S2, in which case ∫∫S1∪S2fdA=∫∫S1fdA+∫∫S2fdA.
If f and g are integrable on S and f(x)≤g(x) for x∈S, then ∫∫SfdA≤∫∫SgdA
If f is integrable on S, then so is ∣f∣, and ∣∫∫SfdA∣≤∫∫S∣f∣dA
A set Z⊂R2 has zero content if for any ϵ>0, there is a finite collection of rectangles which cover Z and the sum of their areas is less than $$\epsilon
Theorem 4.18. Suppose f is a bounded function on the rectangle R. If the set of points in R at which f is discontinuous has zero content, then f is integrable on R.
Smooth curves can in fact have zero content
Proposition 4.19.
If Z⊂R2 has zero content and U⊂Z, then U has zero content.
If Z1,...,Zk have zero content, then so does ⋃1kZj.
If f:(a0,b0)→R2 is of class C1, then f([a,b]) has zero content whenever a0<a<b<b0
Lemma 4.20. The function χS is discontinuous at x iff x is in the boundary of S.
We need the boundary of a set to have zero content. A set S⊂R2 is Jordan measurable if it is boudned and its boundary has zero content.
Any bounded set whose boundary is a finite union of pieces of smooth curves is measurable
Theorem 4.21. Let s be a measurable subset of R2. Suppose f:R2→R is bounded adn the set of points in S at which f is discontinuous has zero content. Then f is integrable on S.
Proposition 4.22. Suppose Z⊂R2 has zero content. If f:R2→R is boounded, then f is integrable on Z and ∫∫ZfdA=0.
Corollary 4.23.
Suppose f is integrable on S⊂R2. If g is bounded and g(x)=f(x) except for x in a set of zero content, then g is integrable on S and ∫∫SgdA=∫∫SfdA
Suppose f is integrable on S,T, and \(S \intersect T\) has zero content. Then f is integrable on S∪T. We have ∫∫S∪TfdA=∫∫SfdA+∫∫TfdA
If S is any Jordan measurable set in a plane, its area is the integral over SS of the constant function f(x)≡1.
area(S)=∫∫S1dA=∫∫χSdA
Theory of n-dimensional integrals – need to use n-dimensional rectangular boxes in Rn
A bounded set Z⊂Rn has zero content iff for any ϵ>0 there are rectangular boxes R1,...,Rk whose total volume is less than ϵ, where the union of Rj is a cover for Z.
Theorem 4.24. (The Mean Value Theorem for Integrals.) Let S be a compact, connected, measurable subset of Rn, and let f,g be continuous functions on S with g≥0. Then there is a point a∈S such that ∫...∫Sf(x)g(x)dnx=f(a)∫...∫Sg(x)dnx.
Corollary 4.25. Let S be a compact, connected, measurable subset of Rn. Let f be a continuous function on S. Then there is a point a∈S such that ∫...∫Sf(x)dnx=f(a)∣S∣ – this is the average of mean value of f on S
4.3: Multiple Integrals and Iterated Integrals
In the case of n=2, we should have that
∫∫RfdA=∫cd[∫abf(x,y)dx]dy
Integrability of f on R does not need to imply the integrability of f(x,y0) as a function of x for fixed y0 on [a,b]
A line segment is a set of zero content, so in fact it could be discontinuous at every point in it
Theorem 4.26. Let R be a rectangle bounded by [a,b] in x and [c,d] in y. Let f be an integrable function in R. Suppose that the “slices” in each dimension are integrable. Then
∫∫RfdA=∫cd[∫abf(x,y)dx]dy=∫ab[∫cdf(x,y)dy]dx
Iterated integrals
An integral over an n-dimensional rectangular solid can be evaluated as an n-fold iterated integral
Under suitable conditions for the integrand f, the order of integration in an iterated integral can be reversed.
4.4: Change of Variables for Multiple Integrals
If g is a one-to-one function of class C1 on the interval [a,b], then for a continous function f,
∫abf(g(u))g′(u)du=∫g(a)g(b)f(x)dx
Sometimes have to compensate for the ‘right order’ of the bounds because g might reverse them
∫If(x)dx=∫g−1(I)f(g(u))∣g′(u)∣du
Suppose G is a one-to-one transformation from a region R to another region S. R=G−1(S)
Area of any matrix A as a transformation on the unit matrix is the absolute value of the determinant of A
∫∫Sf(x,y)dxdy=∣ad−bc∣∫∫G−1(S)f(au+bv,cu+dv)dudv
Theorem 4.37. Let A be an invertible n×n matrix, and let G(u)=Au be the corresponding linear transformation of Rn. Suppose S is a measurable region in Rn and f is an integrable function on S. Then G−1(S)={A−1x:x∈S} is measurable and f∘G is integrable on G−1(S), and
∫...∫Sf(x)dnx=∣detA∣∫...∫G−1(S)f(Au)dnu
Theorem 4.41. Given open sets U,V in Rn, let G:U→V be a one-to-one transformation of class C1 whose derivative DG(u) is invertible for all u∈U. Suppose that T⊂U and S⊂V are measurable sets such that Tˉ⊂U and G(T)=S. If f is an integrable function on S, then f∘G is integrable on T, and
∫...∫Sf(x)dnx=∫...∫Tf(G(u))∣detDG(u)∣dnu
4.5: Functions defined by integrals
We can form functions out of integrating variables. How do properties of f relate to properties of F?
To limits commute across integral operations? In general, the answer is no.
Theorem 4.46. Suppose S,T are compact subsets of Rn and Rm, respectively, and S is measurable. If \(f(x, y)$ is continuous on the set\)T \times S,thenthefunctionFdefinedbyF(x) = \int … \int_S f(x, y) d^n yiscontinuousonT$$.
Theorem 4.47. Suppose S⊂Rn is compact and measurable, and T⊂Rm is open. If f and ∇xf are continuous on T×S, then the function F is of class C1 on T, and
∂xj∂F(x)=∫...∫Spartialxj∂f(x,y)dny
Theorem 4.52. (Bounded Convergence Theorem.) Let S be a measurable subset of Rn and {fj} be a sequence of integrable functions on S. SUppose fj(y)→f(y) for each y∈S, where f is an integrable function on S, and there is a constant C such that ∣fj(y)∣≤C for all j and all y∈S. Then,
j→∞lim∫...∫Sfj(y)dny=∫...∫Sf(y)dny
4.6: Improper Integrals
Type I proper integrals: ∫a∞f(x)dx, f integrable over every finite subinterval [a,b]
Type II proper integrals: ∫abf(x)dx, f integrable over [c,b] for every c>a but unbounded near $$x = a$4
∫a∞f(x)dx=b→∞lim∫abf(x)dx
The integral converges if the RHS limit exists; otherwise, the limit diverges
Does ∫a∞f(x)dx converge?
Lemma 4.54. If ϕ is a bounded increasing function on [a,∞), then limx→∞ϕ(x) exists and equals sup{ϕ(x):x≥a}.
The integral ∫a∞f(x)dx converges iff ∫abf(x)dx remains bounded as b→∞
Theorem 4.55. Suppose that 0≤f(x)≤g(x) for all sufficiently large x. If ∫a∞g(x)dx converges, so does ∫a∞f(x)dx. If ∫a∞f(x)dx diverges, so does ∫a∞g(x)dx.
Corollary 4.56. Suppose f>0, g>0, f(x)/g(x)→l as x→∞. If 0<l<∞, then ∫a∞f(x)dx and ∫a∞g(x)dx are both convergent or both divergent. If l=0, the convergence of ∫a∞g(x)dx implies the convergence of ∫a∞f(x)dx. If l=∞, the divergence of ∫a∞g(x)dx implies the divergence of ∫a∞f(x)dx.
Corollary 4.57. If 0≤f(x)≤Cx−p for all sufficiently large x, where p>1, then ∫a∞f(x)dx converges. If f(x)≥cx−1(c>0) for all sufficiently large x, then ∫a∞f(x)dx diverges.
There are functions whose rate of decay at infinity is faster than x−1 but slower than x−p for any p>1, and their integrals can converge or diverge.
Theorem 4.58. If ∫a∞∣f(x)∣dx converges, then ∫a∞f(x)dx converges.
integral is absolutely convergent if the same integral with absolute value of the function converges.
The integral may converge even if the absolute integral does not converge because of cancellation effects in positive and negative values.
Type II integrals
∫abf(x)dx=c>a,c→alim∫cbf(x)dx
∫abf(x)dx converges if the RHS limit and diverges otherwise
Theorem 4.59. Suppose that 0≤f(x)≤g(x) fro all x sufficiently close to a. If ∫abg(x)dx converges, so does ∫abf(x)dx. If ∫abf(x)dx diverges, so does ∫abg(x)dx.